Triangle ABC has M on AB and N on AC. Drag MN while it stays parallel to BC, or release the constraint and move either intersection. Compare the measurements and ratios in the observation panel.
MN ∥ BC
Model measurements (cm)
Drag MN; compare AM/AB and AN/AC.
Select or focus a segment name in a fraction to highlight it in the diagram.
The two ratios are equal
MN is parallel to BC
=
5.213
=0.400
=
615
=0.400
Displayed measurements are rounded; comparisons use the model values.
AM
5.2 cm
MB
7.8 cm
AN
6 cm
NC
9 cm
AB
13 cm
AC
15 cm
If MN ∥ BC, with M on AB and N on AC, corresponding segments on the two sides have equal ratios.
As MN moves, the common value can change. What stays true is that the two ratios are equal.
Loading resourceModel notes
The model uses nondegenerate triangles, with M inside AB and N inside AC. The 10–90% control range keeps the diagram readable; the theorem is not limited to that range.
Lengths are centimetres in an ideal model. Displayed numbers are rounded, but comparisons use original values; screen sizes are not physical ruler measurements.
Releasing the constraint lets the points move independently; the lines can still be parallel when both points divide their sides at the same fraction.
The interaction illustrates the theorem and does not replace a general proof. This version does not cover intersections on extended sides or directed lengths.
Triangle proportionality — Parallel lines preserve ratios | Public library